Chemistry Department

CHEM 1A

 Tips


this link will take you to a brief discussion of normality

Redox equations

This is a link for practicing balancing redox equations. http://www.mpcfaculty.net/mark_bishop/redox_balance_Half_Acid.htm

This is a link for practicing balancing redox equations.http://www.mpcfaculty.net/mark_bishop/redox_balance_Half_Base.htm

CATIONS

 

Easy:  These cations have only one oxidation state.  The name of the ion is the same as the name of the element in both the IUPAC (Stock) and classical systems.

 

1+ :      Li + , Na + , K + , Rb + , Cs + , Ag + , NH4+ , (ammonium)

2+ :      Be 2+ , Mg 2+ , Ca 2+ , Sr 2+ , Ba 2+ , Zn 2+ , Cd 2+

3+ :      Al 3+

 

Difficult:  These ions have two (or more) oxidation states.

            IUPAC uses Roman numerals ( I, II, III, IV, V, VI ) to indicate oxidation state

            Classical uses word endings to indicate to indicate oxidation states.  Some of these stems are derived from the             Latin name for the element.            stemous indicates the lower oxidation state

                                                            stemic indicates the higher oxidation state

 

1+, 2+

 

 

 

 

 

 

 

Cu +

copper(I)

cuprous

Hg 2 2+

mercury(I)

mercurous

 

Cu 2+

copper(II)

cupric

Hg 2+

mercury(II)

mercuric

2+, 3+

 

 

 

 

 

 

 

Co 2+

cobalt(II)

cobaltous

Cr 2+

chromium(II)

chromous

 

Co 3+

cobalt(III)

cobaltic

Cr 3+

chromium(III)

chromic

 

Fe 2+

iron(II)

ferrous

Mn 2+

manganese(II)

manganous

 

Fe 3+

iron(III)

ferric

Mn 3+

manganese(III)

manganic

 

Ni 2+

nickel(II)

nickelous

Mn 4+

manganese(IV

?

 

Ni 3+

nickel(III)

nickelic

 

 

 

2+, 4+

 

 

 

 

 

 

 

Pb 2+

lead(II)

plumbous

Sn 2+

tin(II)

stannous

 

Pb 4+

lead(IV)

plumbic

Sn 4+

tin(IV)

stannic

3+, 5+

 

 

 

 

 

 

 

As 3+

arsenic(III)

arsenous

Sb 3+

antimony(III)

antimonous

 

As 5+

arsenic(v)

arsenic

Sb 5+

antimony(V)

antimonic

 

ANIONS

 

Monatomic:  binary compounds ( the ion may be used more than once in the formula, i.e.  Al2S3 )

                        anion name = (stem)ide,  i.e.  H – is hydride.

1– :       H – (hydr),  F – (fluor),  Cl – (chlor),  Br – (brom),  I – (iod) 

2– :       O (ox),  S (sulf, in acids = sulfur)

3– :       N (nitr),  P (phosph,  in acids = phosphor),  As (arsen),  Sb (antimon)

 

Polyatomic:  (named as though binary)

 

1–:        OH – (hydroxide),  CN – (cyanide)

2–:        O 2 (peroxide)

 

Polyatomic:  ( oxoanions — ternary or higher)

 

 

 

 

 

 

 

 

C2H3O2 –

acetate

NO3 –

nitrate

ClO –

hypochlorite

 

HCO3–

hydrogencarbonate

bicarbonate

NO2–

nitrite

ClO2–

chlorite

 

SCN–

thiocyanate

BrO3 –

bromate

ClO3 –

chlorate

 

MnO4–

permanganate

IO4 –

periodate

ClO4 –

perchlorate

 

 

 

 

 

 

 

CO3

carbonate

CrO4

chromate

SO4

sulfate

 

C2O4

oxalate

Cr2O7

dichromate

SO3

sulfite

 

 

 

 

 

 

 

AsO4

arsenate

PO4

phosphate

 

 

 

AsO3

arsenite

PO3

phosphite

 

 

 

Numerical prefixes:

             1 - mono    2 - di                 3 - tri                 4 - tetra             5 - penta    6 - hexa                      

            7 - hepta    8 - octa             9 - nona            10 - deca

 

Binary acids:              hydrostemic acid    (stem is stem of the anion name)

 

oxoacids:

            oxoanion ending in stemate becomes stemic acid

            oxoanion ending in stemite becomes stemous acid

 

 

 

 

CATIONS

 

Easy:  These cations have only one oxidation state.  The name of the ion is the same as the name of the element in both the IUPAC (Stock) and classical systems.

 

1+ :      Li + , Na + , K + , Rb + , Cs + , Ag + , NH4+ , (ammonium)
2+ :      Be 2+ , Mg 2+ , Ca 2+ , Sr 2+ , Ba 2+ , Zn 2+ , Cd 2+
3+ :      Al 3+

 

Difficult:  These ions have two (or more) oxidation states.

            IUPAC uses Roman numerals ( I, II, III, IV, V, VI ) to indicate oxidation state

            Classical uses word endings to indicate to indicate oxidation states.  Some of these stems are derived from the Latin name for the element.           

stemous indicates the lower oxidation; state stemic indicates the higher oxidation state

                                                             

1+, 2+

 

 

 

 

 

 

 

Cu +

copper(I)

cuprous

Hg 2 2+

mercury(I)

mercurous

 

Cu 2+

copper(II)

cupric

Hg 2+

mercury(II)

mercuric

2+, 3+

 

 

 

 

 

 

 

Co 2+

cobalt(II)

cobaltous

Cr 2+

chromium(II)

chromous

 

Co 3+

cobalt(III)

cobaltic

Cr 3+

chromium(III)

chromic

 

Fe 2+

iron(II)

ferrous

Mn 2+

manganese(II)

manganous

 

Fe 3+

iron(III)

ferric

Mn 3+

manganese(III)

manganic

 

Ni 2+

nickel(II)

nickelous

Mn 4+

manganese(IV)

?

 

Ni 3+

nickel(III)

nickelic

 

 

 

2+, 4+

 

 

 

 

 

 

 

Pb 2+

lead(II)

plumbous

Sn 2+

tin(II)

stannous

 

Pb 4+

lead(IV)

plumbic

Sn 4+

tin(IV)

stannic

3+, 5+

 

 

 

 

 

 

 

As 3+

arsenic(III)

arsenous

Sb 3+

antimony(III)

antimonous

 

As 5+

arsenic(v)

arsenic

Sb 5+

antimony(V)

antimonic

 

ANIONS

 

Monatomic:  binary compounds ( the ion may be used more than once in the formula, i.e.  Al2S3 )

                        anion name = (stem)ide,  i.e.  H – is hydride.

 

1– :       H – (hydr),  F – (fluor),  Cl – (chlor),  Br – (brom),  I – (iod)
2– :       O (ox),  S (sulf, in acids = sulfur)
3– :       N (nitr),  P (phosph,  in acids = phosphor),  As (arsen),  Sb (antimon)

 

Polyatomic:  (named as though binary)

 

1–:        OH – (hydroxide),  CN – (cyanide)
2–:        O 2 (peroxide)

Polyatomic:  ( oxoanions — ternary or higher)

 

 

 

 

 

 

 

 

C2H3O2 –

acetate

NO3 –

nitrate

ClO –

hypochlorite

 

HCO3–

hydrogencarbonate

(bicarbonate)

NO2–

nitrite

ClO2–

chlorite

 

SCN–

thiocyanate

BrO3 –

bromate

ClO3 –

chlorate

 

MnO4–

permanganate

IO4 –

periodate

ClO4 –

perchlorate

 

 

 

 

 

 

 

CO3

carbonate

CrO4

chromate

SO4

sulfate

 

C2O4

oxalate

Cr2O7

dichromate

SO3

sulfite

 

 

 

 

 

 

 

AsO4

arsenate

PO4

phosphate

 

 

 

AsO3

arsenite

PO3

phosphite

 

 

 

Numerical prefixes:

           

            1 - mono    2 - di         3 - tri         4 - tetra       5 - penta     6 - hexa      7 - hepta    8 - octa         9 - nona        10 - deca

          

 

Binary acids:              hydrostemic acid    (stem is stem of the anion name)

 

oxoacids:

            oxoanion ending in stemate becomes stemic acid

            oxoanion ending in stemite becomes stemous acid

 

Equivalents, Equivalent Weight, and Normality

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Stoichiometric calculations are performed using moles and mole ratios (obtained from a chemical formula or balanced equation).  However in the laboratory, when working with unknowns, it is necessary to work with equivalencies.  Then x equivalents of reagent A will completely react with the same number of equivalents of reagent B (i.e. x equivalents of B).  One equivalent of a reagent is that amount of reagent that will produce (or use) one mole of electrons.  In acid base reactions, where there is no electron change, we can consider the potential number of electrons.  One mole of H+ ions could gain one mole of electrons to form one half mole of H2 (g).   1 H+   +   1 e–  =   ½  H2 (g)  .  Using a to represent the number of equivalents (eq) per mole, we can relate the equivalent weight (or equivalent mass) to the formula weight (or formula mass) by

 

equivalent weight   =   formula weight / a

 

or for short

 

eq wt  =  f wt / a

 

Where a can represent 

  1. the number of moles of electrons (lost or gained)
  2. the number of H+ ions reacting (for acids)
  3. the number of OH– ions reacting (for bases)

 

Just as we defined

 

molarity (M)  =  (moles of solute) / (liters of solution)  or  M  = moles/L ;

 

we can define

 

normality (N)  =  (equivalents of solute) / (liters of solution)  or  N  =  eq/L.

 

where,

 

equivalents of solute (eq)   =  mass / equivalent weight  or  eq  =  m / eq wt

 

The relationship between normality and molarity would be

 

N  =  a M .

 

            The reason for introducing equivalents is so we can write

 

eqA  =  eqB

 

or

 

LANA  =  LBNB

 

Although there is no mole ratio in this equation, the mole ratio information is contained in the calculation of the factor a.  There is also an implication that acids and bases react completely.  If there is a partial reaction (such as H3PO4 going to NaH2PO4, etc) , there is enough information to write a balanced equation, and the calculation should be done using moles and mole ratios.

 

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